Indented the 2 formulae
Okumaya devam et...
← Previous revision | Revision as of 01:21, 5 May 2024 |
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| Power output in [[SI units]] may be calculated as follows: | Power output in [[SI units]] may be calculated as follows: |
| Rotary power (in [[newton-meter]]s per second, N·m/s) = 2[[pi|π]] × the distance from the center-line of the drum (the friction device) to the point of measurement (in [[meter]]s, m) × rotational speed (in [[revolutions per second]]) × measured force (in [[Newton (unit)|newtons]], N).<ref>Kemp’s Engineer’s Year Book</ref><ref>Reeds Applied Mechanics for Engineers</ref> | :Rotary power (in [[newton-meter]]s per second, N·m/s) = 2[[pi|π]] × the distance from the center-line of the drum (the friction device) to the point of measurement (in [[meter]]s, m) × rotational speed (in [[revolutions per second]]) × measured force (in [[Newton (unit)|newtons]], N).<ref>Kemp’s Engineer’s Year Book</ref><ref>Reeds Applied Mechanics for Engineers</ref> |
| Or in [[Imperial units]]: | Or in [[Imperial units]]: |
| Rotary power (in [[Pound-foot (torque)|pound-feet]] per second, lbf·ft/s) = 2[[pi|π]] × distance from center-line of the drum (the friction device) to the point of measurement (in feet, ft) × rotational speed (in [[revolutions per second]]) × measured force (in [[Pound-force|pounds]], lbf). | :Rotary power (in [[Pound-foot (torque)|pound-feet]] per second, lbf·ft/s) = 2[[pi|π]] × distance from center-line of the drum (the friction device) to the point of measurement (in feet, ft) × rotational speed (in [[revolutions per second]]) × measured force (in [[Pound-force|pounds]], lbf). |
| ==References== | ==References== |
Okumaya devam et...